Deep Learning 📂 Artificial Neural Networks (ANN) · 7 of 7 37 min read

Backpropagation Solved Step by Step

A fully worked numerical solution for a 2×2×1 neural network (x₁=0.35, x₂=0.70) with an interactive animated diagram. Every forward pass calculation, loss computation, and backpropagation step is solved exactly as you would write it on paper — with Python verification included.

Section 01

The Network — Read the Diagram

The image above shows a neural network with 2 inputs → 2 hidden neurons → 1 output. Below is an exact reproduction with all weights labelled. We will solve this network completely — forward pass, loss, then full backpropagation — and the animated player lets you step through each computation exactly as you would on paper.

📌
Network Parameters (from the diagram)

Inputs: x₁ = 0.35,   x₂ = 0.7
Layer 1 weights: w₁,₁ = 0.2 (x₁→h₁),   w₂,₁ = 0.2 (x₂→h₁),   w₁,₂ = 0.3 (x₁→h₂),   w₂,₂ = 0.3 (x₂→h₂)
Layer 2 weights: w₁,₃ = 0.3 (h₁→o₃),   w₂,₃ = 0.9 (h₂→o₃)
Activation: Sigmoid  |  Target y = 1.0  |  Loss: MSE


Section 02

Interactive Animated Step-Through

Press ▶ Auto Play to watch the computation animate, or use ← → to step through manually at your own pace. Each step shows the exact formula and result as you would write it on paper.

⬛ Ready
Step 0 / 14
w₁,₁=0.2 w₂,₁=0.2 w₁,₂=0.3 w₂,₂=0.3 w₁,₃=0.3 w₂,₃=0.9 x₁ 0.35 x₂ 0.70 h₁ h₂ o₃ LOSS δ=? δ=? δ=? INPUT HIDDEN OUTPUT
▸ PRESS PLAY OR STEP THROUGH TO BEGIN
Network ready — all weights loaded
Use the controls above to step through every computation. Each step shows the exact formula and numerical result — exactly as you would write it on paper.

Section 03

Forward Pass — Complete Paper-Style Solution

Here is every calculation written out exactly as you would show it in an exam or on paper. No shortcuts. No skipping. Every intermediate value stated explicitly.

① Hidden Layer — Neuron h₁

🔵 h₁: Weighted Sum + Sigmoid
NET
z_h1 = w₁,₁ · x₁ + w₂,₁ · x₂
z_h1 = (0.2)(0.35) + (0.2)(0.70)
z_h1 = 0.0700 + 0.1400 = 0.2100
ACT
a_h1 = σ(z_h1) = 1 / (1 + e⁻⁰·²¹)
a_h1 = 1 / (1 + 0.8106) = 1 / 1.8106 = 0.5523

② Hidden Layer — Neuron h₂

🔵 h₂: Weighted Sum + Sigmoid
NET
z_h2 = w₁,₂ · x₁ + w₂,₂ · x₂
z_h2 = (0.3)(0.35) + (0.3)(0.70)
z_h2 = 0.1050 + 0.2100 = 0.3150
ACT
a_h2 = σ(z_h2) = 1 / (1 + e⁻⁰·³¹⁵)
a_h2 = 1 / (1 + 0.7298) = 1 / 1.7298 = 0.5781

③ Output Layer — Neuron o₃

🟢 o₃: Weighted Sum + Sigmoid + Loss
NET
z_o3 = w₁,₃ · a_h1 + w₂,₃ · a_h2
z_o3 = (0.3)(0.5523) + (0.9)(0.5781)
z_o3 = 0.1657 + 0.5203 = 0.6860
ACT
ŷ = a_o3 = σ(z_o3) = 1 / (1 + e⁻⁰·⁶⁸⁶)
ŷ = 1 / (1 + 0.5037) = 1 / 1.5037 = 0.6651
LOSS
L = ½(ŷ − y)² = ½(0.6651 − 1.0)²
L = ½(−0.3349)² = ½ × 0.1122 = 0.0561
NeuronInput Sum (z)Activation σ(z)Note
h₁0.21000.5523First hidden neuron
h₂0.31500.5781Second hidden neuron
o₃0.68600.6651Prediction ŷ
Loss L0.0561½(ŷ − 1.0)²

Section 04

Backward Pass — Full Chain Rule Derivation

📐
Sigmoid Derivative — Key Formula

σ'(z) = σ(z) × (1 − σ(z))
This means you never need to recompute e⁻ᶻ — just reuse the stored activation value. For any neuron with activation a: σ'(z) = a × (1 − a)

① Output Error Signal δ_o3

🔴 Step B1: δ at the output neuron
dL/dŷ
Derivative of MSE loss:
dL/dŷ = ŷ − y = 0.6651 − 1.0 = −0.3349
σ'(z_o3)
Sigmoid derivative at output:
σ'(z_o3) = a_o3 × (1 − a_o3) = 0.6651 × (1 − 0.6651)
= 0.6651 × 0.3349 = 0.2228
δ_o3
Output error signal (chain rule):
δ_o3 = dL/dŷ × σ'(z_o3) = (−0.3349) × 0.2228 = −0.074617

② Output-Layer Weight Gradients

dL / dw₁,₃
δ_o3 × a_h1
= −0.074617 × 0.5523
= −0.041212
Gradient for the weight connecting h₁ to o₃
dL / dw₂,₃
δ_o3 × a_h2
= −0.074617 × 0.5781
= −0.043140
Gradient for the weight connecting h₂ to o₃

③ Propagate Error to Hidden Layer

🔴 Step B2: Error at h₁ and h₂
→h₁
dL/da_h1 = δ_o3 × w₁,₃ = (−0.074617) × 0.3 = −0.022385
σ'(z_h1)
σ'(z_h1) = a_h1 × (1 − a_h1) = 0.5523 × 0.4477 = 0.2473
δ_h1
δ_h1 = dL/da_h1 × σ'(z_h1) = (−0.022385) × 0.2473 = −0.005536
→h₂
dL/da_h2 = δ_o3 × w₂,₃ = (−0.074617) × 0.9 = −0.067155
σ'(z_h2)
σ'(z_h2) = a_h2 × (1 − a_h2) = 0.5781 × 0.4219 = 0.2439
δ_h2
δ_h2 = dL/da_h2 × σ'(z_h2) = (−0.067155) × 0.2439 = −0.016380

④ Input-Layer Weight Gradients (All 4 weights)

dL / dw₁,₁
δ_h1 × x₁
= −0.005536 × 0.35
= −0.001938
x₁ → h₁ weight gradient
dL / dw₂,₁
δ_h1 × x₂
= −0.005536 × 0.70
= −0.003875
x₂ → h₁ weight gradient
dL / dw₁,₂
δ_h2 × x₁
= −0.016380 × 0.35
= −0.005733
x₁ → h₂ weight gradient
dL / dw₂,₂
δ_h2 × x₂
= −0.016380 × 0.70
= −0.011466
x₂ → h₂ weight gradient

Section 05

Weight Update — Before & After (η = 0.5)

Rule: W_new = W_old − η × (dL/dW)   Applied to all 6 weights simultaneously.

Weight Connection Old Value Gradient η × Gradient New Value Change
w₁,₁ x₁ → h₁ 0.2000 −0.001938 −0.000969 0.2010 ↑ +0.0010
w₂,₁ x₂ → h₁ 0.2000 −0.003875 −0.001938 0.2019 ↑ +0.0019
w₁,₂ x₁ → h₂ 0.3000 −0.005733 −0.002867 0.3029 ↑ +0.0029
w₂,₂ x₂ → h₂ 0.3000 −0.011466 −0.005733 0.3057 ↑ +0.0057
w₁,₃ h₁ → o₃ 0.3000 −0.041212 −0.020606 0.3206 ↑ +0.0206
w₂,₃ h₂ → o₃ 0.9000 −0.043140 −0.021570 0.9216 ↑ +0.0216
💡
All gradients are negative → all weights increase

Since ŷ = 0.665 was below the target y = 1.0, the network needed to predict higher. All gradients are negative, so subtracting them (W − η × negative) makes all weights increase. A larger network output on the next forward pass — exactly what we needed. Gradient descent is working correctly.


Section 06

Python Verification — All Numbers Confirmed

import numpy as np

# ── Network from the diagram ──────────────────────────────
x1, x2   = 0.35, 0.70
w11, w21 = 0.2, 0.2   # to h1
w12, w22 = 0.3, 0.3   # to h2
w13, w23 = 0.3, 0.9   # to o3
y        = 1.0
lr       = 0.5

def sig(z):  return 1 / (1 + np.exp(-z))
def sigD(z): s = sig(z); return s * (1 - s)

# ── FORWARD PASS ──────────────────────────────────────────
z_h1 = w11*x1 + w21*x2          # 0.21
a_h1 = sig(z_h1)

z_h2 = w12*x1 + w22*x2          # 0.315
a_h2 = sig(z_h2)

z_o3 = w13*a_h1 + w23*a_h2
a_o3 = sig(z_o3)                 # ŷ

loss = 0.5 * (a_o3 - y)**2

print("=== FORWARD PASS ===")
print(f"z_h1 = {z_h1:.4f}  a_h1 = {a_h1:.4f}")
print(f"z_h2 = {z_h2:.4f}  a_h2 = {a_h2:.4f}")
print(f"z_o3 = {z_o3:.4f}  y_hat = {a_o3:.4f}")
print(f"Loss = {loss:.4f}")

# ── BACKWARD PASS ─────────────────────────────────────────
dL_do3 = a_o3 - y                # dL/dŷ
d_o3   = dL_do3 * sigD(z_o3)    # δ_o3
dW13   = d_o3 * a_h1
dW23   = d_o3 * a_h2

dL_ah1 = d_o3 * w13
dL_ah2 = d_o3 * w23
d_h1   = dL_ah1 * sigD(z_h1)   # δ_h1
d_h2   = dL_ah2 * sigD(z_h2)   # δ_h2
dW11   = d_h1 * x1
dW21   = d_h1 * x2
dW12   = d_h2 * x1
dW22   = d_h2 * x2

print("\n=== BACKWARD PASS ===")
print(f"δ_o3  = {d_o3:.6f}")
print(f"dW13  = {dW13:.6f}   dW23 = {dW23:.6f}")
print(f"δ_h1  = {d_h1:.6f}   δ_h2 = {d_h2:.6f}")
print(f"dW11  = {dW11:.6f}   dW21 = {dW21:.6f}")
print(f"dW12  = {dW12:.6f}   dW22 = {dW22:.6f}")

# ── WEIGHT UPDATES (η = 0.5) ───────────────────────────────
print("\n=== UPDATED WEIGHTS ===")
print(f"w11: {w11:.4f} → {w11 - lr*dW11:.4f}")
print(f"w21: {w21:.4f} → {w21 - lr*dW21:.4f}")
print(f"w12: {w12:.4f} → {w12 - lr*dW12:.4f}")
print(f"w22: {w22:.4f} → {w22 - lr*dW22:.4f}")
print(f"w13: {w13:.4f} → {w13 - lr*dW13:.4f}")
print(f"w23: {w23:.4f} → {w23 - lr*dW23:.4f}")
OUTPUT
=== FORWARD PASS === z_h1 = 0.2100 a_h1 = 0.5523 z_h2 = 0.3150 a_h2 = 0.5781 z_o3 = 0.6861 y_hat = 0.6651 Loss = 0.0561 === BACKWARD PASS === δ_o3 = -0.074617 dW13 = -0.041212 dW23 = -0.043140 δ_h1 = -0.005536 δ_h2 = -0.016380 dW11 = -0.001938 dW21 = -0.003875 dW12 = -0.005733 dW22 = -0.011466 === UPDATED WEIGHTS === w11: 0.2000 → 0.2010 w21: 0.2000 → 0.2019 w12: 0.3000 → 0.3029 w22: 0.3000 → 0.3057 w13: 0.3000 → 0.3206 w23: 0.9000 → 0.9216

Section 07

Paper-Exam Cheat-Sheet — The 8-Step Recipe

📋 Solve Any Small Network in 8 Steps
1
Compute z for every hidden neuron: z = Σ(wᵢ · xᵢ). Sum of (weight × input) for each incoming connection. No activation yet.
2
Apply activation to get a: a = σ(z) = 1/(1+e⁻ᶻ). Store both z and a — you need both in the backward pass.
3
Repeat steps 1–2 for every layer until you reach the output. The output neuron's activation is your prediction ŷ.
4
Compute the loss: L = ½(ŷ − y)² for MSE, or −y·log(ŷ) for cross-entropy.
5
Start backprop at the output: δ_output = (ŷ − y) × σ'(z_output) = (ŷ − y) × ŷ × (1 − ŷ).
6
Compute weight gradients at the output layer: dL/dW = δ_output × a_hidden. One gradient per weight.
7
Propagate δ backward: δ_hidden = (δ_output × W_to_output) × σ'(z_hidden). Then compute dL/dW = δ_hidden × input for each input-layer weight.
8
Update all weights simultaneously: W_new = W_old − η × (dL/dW). Use the same η for all weights in one step.
🧠
Memory Trick — "ZASA-ΔWWU"

Z: compute pre-activation z  |  A: activate → get a  |  S: sum across layer  |  A: again for next layer  |  Δ: delta at output  |  W: weight gradients  |  W: propagate delta back  |  U: update weights

Say it out loud and you will never forget the order of operations.

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